Any line perpendicular to some line with slope a must have a slope -1/a
Then, any line with slope 1/5 will be perpendicular to the line y = -5x - 4
Now consider a line perpendicular to y = -5x - 4 passing through (-10,2). If b is your intercept, we have:
[tex]\begin{gathered} y=\frac{x}{5}+b \\ 2=-\frac{10}{5}+b \\ 2=-2+b \\ b=4 \end{gathered}[/tex]
Therefore, the line is:
[tex]y=\frac{x}{5}+4[/tex]
