Let us draw a sketch to understand the question
We need to find the coordinates of the point (-x, y)
Since cos(60) = adjacent/hypotenuse
Since the adjacent = x
Since the hypotenuse = 20, then
[tex]cos\left(60\right)=\frac{x}{20}[/tex]
By using the cross-multiplication
[tex]x=20cos\left(60\right)[/tex]
Since x must be negative
Since cos(60) = 0.5, then
[tex]\begin{gathered} x=-20\left(0.5\right) \\ x=-10 \end{gathered}[/tex]
Since sin(60) = opposite/hypotenuse
Since the opposite = y
Since the hypotenuse = 20, then
[tex]sin\left(60\right)=\frac{y}{20}[/tex]
By using the cross multiplication, then
[tex]\begin{gathered} y=20sin\left(60\right) \\ y=20\left(\frac{\sqrt{3}}{2}\right? \\ y=10\sqrt{3} \end{gathered}[/tex]
Change it to decimal and round it to the nearest hundredth, then
[tex]y=17.32[/tex]
The x component of the coordinates is -10
The y component of the coordinate is 17.32
