For the seesaw to be balanced we need the torques each child apply on the seesaw to be equal, that is:
[tex]\tau_1=\tau_2[/tex]Where he torque is given by:
[tex]\tau=Fr[/tex]where F is the force each child applies and r is the distance from the pivot. For child one we know that it applies its weight, tha ihis mass is 25 kg and the distance is 1.5 m; for child two we know that it applies its weight and the distance is hat we need to find, then we have:
[tex]\begin{gathered} (25)(9.8)(1.5)=(9.8)(35)r_2 \\ r_2=\frac{(25)(1.5)}{(35)} \\ r_2=1.07 \end{gathered}[/tex]Therefore, the distance from child two from the pivot has to be 1.07 m
