Respuesta :

[tex]\begin{gathered} 3x+y\leq6 \\ y\leq6-3x \\ \text{when x=0} \\ y\leq6 \end{gathered}[/tex][tex]\begin{gathered} y\leq-\frac{1}{3}x+2 \\ \text{when x=0} \\ y\leq2 \end{gathered}[/tex]

The graph is therefore A. Note the graphs

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