the equation is
[tex]1.25\text{ e + 0.50 c = 8}[/tex]Clearing c, we have
[tex]c\text{ = }\frac{8-1.25\text{ e}}{0.5}\text{ }[/tex]So we just need to make the substitutions. The first one is e = 1.4, so we will have
[tex]c=\frac{8-1.25(1.4)}{.5}=12.5\text{ crabs rangoons}[/tex]For the second one, we have e=2.2
[tex]c=\frac{8-1.25(2.2)}{.5}=10.5\text{ crabs rangoons}[/tex]In the second one, we start with 124 lt of water and we add 9 lt per minute (I think, it doesn't say). So, in this case the equation is
[tex]L\text{ =124+9t,}[/tex]where L is the number of liters of water and t is the time in minutes. First we are asked for the first 4 minutes, so we have
[tex]L\text{ = 124+9(4) = }160\text{ lt after the first 4 minutes}[/tex]Then, after the first 80 minutes we have
[tex]L\text{ = 124+9(80) = }844\text{ lt in the first 80 minutes}[/tex]