Hello, I need some help with this precalculus question for my homework, please HW Q3

EXPLANATION:
We are given the logarithmic equation;
[tex]log_3(x+6)=log_38[/tex]After removing the logarithm, we would now have;
[tex]x+6=8[/tex]Therefore the solution set is;
[tex]x+6=8[/tex][tex]\begin{gathered} Subtract\text{ }6\text{ }from\text{ }both\text{ }sides: \\ x+6-6=8-6 \end{gathered}[/tex][tex]x=2[/tex]ANSWER:
The equation is;
[tex]x+6=8[/tex]The solution set is;
[tex]x=2[/tex]