we know that
The average function is equal to
[tex]\frac{f(b)-f(a)}{b-a}[/tex]
In this problem
a=0
b=3
so
[tex]f(a)=f(0)=e^0=1[/tex][tex]f(b)=f(3)=e^3[/tex]
substitute the given values
[tex]\begin{gathered} \frac{e^3-1}{3-0} \\ \frac{e^3-1}{3} \end{gathered}[/tex]
answer is the first option
