Question 17:
Let us redraw the question given with the information given in the question.
The value of the measure of the arc AB is labelled as x degrees. We will apply the angle sum theorem of a triangle to solve this question.
[tex]\begin{gathered} Angle\text{ sum theorem of a triangle:} \\ \text{The sum of angles in a triangle is }180^0 \\ \\ \text{Thus, we can write that:} \\ 27^0+24^0+x^0=180^0 \\ 51^0+x=180^0 \\ \text{Subtract }51^0\text{ from both sides} \\ \\ x=180^0-51^0=129^0 \end{gathered}[/tex]
Question 18:
Let us redraw the circle as follows:
Applying the angle sum theorem of a triangle once more, we have:
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