[tex]f(x)=\frac{x-3}{x+2}[/tex]
The domain of a fuction has conditions when we have an on the denominator because the value of the denominator would be 0 and the deivsion between 0 isnt posible
Then we need to check the values of x than makes 0 the denominator and this values are out of the Domain
[tex]\begin{gathered} x+2=0 \\ x=-2 \end{gathered}[/tex]
So, the Domain is all real values of X such that x is different to -2 , then right option is A
