Answer:
9.48 inches
Explanation:
From the diagram given, in order to level the crane, it will have to be raised by x units.
Using trigonometric ratios:
[tex]\begin{gathered} tan\theta=\frac{\text{Opposite}}{\text{Adjacent}} \\ \implies\tan 7.5\degree=\frac{x}{6} \end{gathered}[/tex]
However, since we are required to give our result in inches, convert 6.0 feet to inches.
[tex]\begin{gathered} 1\text{ feet = 12 Inches} \\ 6\text{ feet = 6 }\times\text{ 12 =72 Inches} \end{gathered}[/tex]
Therefore, we have:
[tex]\tan 7.5\degree=\frac{x}{72}[/tex]
Next, solve for x:
[tex]\begin{gathered} x=72\times\tan 7.5\degree \\ x=72\times0.1317 \\ x=9.48\text{ inches} \end{gathered}[/tex]
Therefore, the downhill side of the base should be raised by 9.48 inches in order to level the crane.
