Given the quadratic equation:
[tex]x^2+9x+8[/tex]To solve it you have to use the quadratic formula
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]For the given function the coefficients are:
a=1
b=9
c=8
Replace them in the formula:
[tex]\begin{gathered} x=\frac{-9\pm\sqrt[]{(9)^2-4\cdot1\cdot8}}{2\cdot1} \\ x=\frac{-9\pm\sqrt[]{81-32}}{2} \\ x=\frac{-9\pm\sqrt[]{49}}{2} \end{gathered}[/tex]Now you have to calculate it using separate ways.
Positive:
[tex]\begin{gathered} x=\frac{-9+\sqrt[]{49}}{2} \\ x=\frac{-9+7}{2} \\ x=\frac{2}{2} \\ x=1 \end{gathered}[/tex]Negative:
[tex]\begin{gathered} x=\frac{-9-\sqrt[]{49}}{2} \\ x=\frac{-9-7}{2} \\ x=-\frac{16}{2} \\ x=-8 \end{gathered}[/tex]The possible values for x are 1 and -8, the correct option is the first one.
