1. Use the given rule to find the coordinates of A'B'C':
[tex]\begin{gathered} (x,y)\rightarrow(x,-y) \\ \\ A(2,-3)\rightarrow A^{\prime}(2,-(-3)) \\ A^{\prime}(2,3) \\ \\ B(4,-2)\rightarrow B^{\prime}(4,-(-2)) \\ B^{\prime}(4,2) \\ \\ C(2,-5)\rightarrow C^{\prime}(2,-(-5)) \\ C^{\prime}(2,5) \end{gathered}[/tex]
2. Graph:
3. Description:
The given transformation is a reflection over x-axis. Points in the image have the same x coordinate than the points in the preimage, but the y coordiante changes of sign (it changes from one side to another of the x-axis)
Then, triangle ABC is refelcted over x-axis to get triangle A'B'C'
