1Jessie draws triangle ABC on a coordinate grid. The slope of line segment AB is \frac{3}{4} 43 . Jessie then transforms triangle ABC using a single transformation to create triangle A'B'C'. She claims the slope of A'B' will still be \frac{3}{4} 43 . For the transformation below, indicate whether it supports or does not support Jessie's claim.Rotation of 180o around the origin.

1Jessie draws triangle ABC on a coordinate grid The slope of line segment AB is frac34 43 Jessie then transforms triangle ABC using a single transformation to c class=

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Explanation

The slope of a line is a measure of its steepness. Mathematically, the slope is calculated as "rise over run" (change in y divided by change in x).

[tex]\text{ Slope }=\frac{\text{ rise}}{\text{ run}}[/tex]

Since the slope of the line segment AB is 3/4, we know that its rise is 3, and its run is 4.

[tex]\text{ Slope of line segment AB }=\frac{\text{ rise}}{\text{ run}}=\frac{3}{4}[/tex]

So, the coordinates of points A and B could be A(0,0) and B(4,3).

On the other hand, the rule for a rotation by 180° about the origin is:

[tex](x,y)\rightarrow(-x,-y)[/tex]

Then we can apply the above rule and calculate the coordinates of line segment A'B'.

[tex]\begin{gathered} A(0,0)\operatorname{\rightarrow}A^{\prime}(0,0) \\ B(4,3)\operatorname{\rightarrow}B^{\prime}(-4,-3) \end{gathered}[/tex]

Finally, let us find the slope of the line segment A'B'.

As we can see, the slope of the line segment A'B' is also 3/4.

[tex]\text{Slope of line segment A'B'}=\frac{\text{r\imaginaryI se}}{\text{run}}=\frac{3}{4}[/tex]Answer

Supports Jessie's claim

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