Given equation
[tex]4x^{\frac{1}{3}}-x=0[/tex]
The first step in solving the equation is to remove the roots
Multiply the equation by the power 3 on both side
[tex](4x^{\frac{1}{3}})^3=x^3[/tex][tex]64x=x^3[/tex]
Now divide the equation with x
[tex]\begin{gathered} \frac{64x}{x}=\frac{x^3}{x} \\ 64=x^2 \end{gathered}[/tex]
Now, taking the square root on the both side of the equation
[tex]\sqrt[]{64}=\sqrt[]{x^2}[/tex][tex]x=\pm8,0[/tex]
the value of x=(-8), 8, 0.
ANSWER:
The first step in solving this equation is cubing the equation.
The second stepp in solving the equation is divide equation with x and taking square root.
For, (-2,2,0)
Put x=(-2)
[tex]\begin{gathered} 4x^{\frac{1}{3}}-x=0 \\ 4(-2)^{\frac{1}{3}}-(-2) \\ 4(-1.259)+2 \\ -5.036+2 \\ -3.036\ne0 \end{gathered}[/tex]
So, x=(-2) is note the solution of the given equation
