What is the molarity (M) of a solution prepared by dissolving 33.2g of NaOH in water to make 750. Ml solution?

The first step to solve this problem is to use the molecular weight of NaOH to convert the given mass to moles (MW=39.997 g/mol):
[tex]33.2g\cdot\frac{mol}{39.997g}=0.83mol[/tex]Now, divide this amount by the volume of the solution (in liters):
[tex]M=\frac{0.83mol}{0.75L}=1.11M[/tex]It means that the correct answer is D. 1.11M.