Recall the following formula for a uniformly accelerated motion:
[tex]\Delta x=v^{}_it+\frac{1}{2}at^2[/tex]
Isolate a from the equation:
[tex]a=\frac{2}{t^2}(\Delta x-v_it)[/tex]
From the formula, notice that a is the unkown variable and that the final velocity does not play a role on solving the problem. In both directions (X and Y), the time must be the same (9.20s), and the rest of the information on the tables is the same.
Therefore, the table which best represents te problem, is:
[tex]\text{Option B}[/tex]
