Using the quadratic formula to solve the equation, we get:
[tex]\begin{gathered} x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x_{1,2}=\frac{1\pm\sqrt[]{(-1)^2-4\cdot3\cdot(-3)}}{2\cdot3} \\ x_{1,2}=\frac{1\pm\sqrt[]{37}}{6} \\ x_1\approx\frac{1+6.08}{6}\approx1.18 \\ x_2\approx\frac{1-6.08}{6}\approx-0.847 \end{gathered}[/tex]Answer: {1.2, -0.8}
