Miguel drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 8 hours. When Miguel drove home, there was no traffic and the trip only took 6 hours. If his average rate was 16 miles per hour faster on the trip home, how far away does Miguel live from the mountains? Do not do rounding .

Respuesta :

Let, the rate of the speed be r.

The distance is given by,

[tex]\text{distance = rate}\times\text{ time}[/tex]

The trip took 8 hours and the distance traveled in 8 hours is,

[tex]D=8r\ldots\ldots\ldots\ldots(1)[/tex]

While retuening , there was no traffic and trip takes 6 hours and average rate is 16 mph faster.

the distance is,

[tex]D=6(r+16)\ldots\ldots\ldots\ldots\ldots(2)[/tex]

Equating both the questions,

[tex]\begin{gathered} 8r=6(r+16) \\ 8r-6r=80 \\ 2r=80 \\ r=40\text{mph} \end{gathered}[/tex]

Distance is,

[tex]\begin{gathered} D=8r \\ D=8\times\frac{80}{3} \\ D=213.3333\text{ miles} \end{gathered}[/tex]

Answer:

Rate is 80/3 mph

distance is 213.3333 miles.

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