Let, the rate of the speed be r.
The distance is given by,
[tex]\text{distance = rate}\times\text{ time}[/tex]The trip took 8 hours and the distance traveled in 8 hours is,
[tex]D=8r\ldots\ldots\ldots\ldots(1)[/tex]While retuening , there was no traffic and trip takes 6 hours and average rate is 16 mph faster.
the distance is,
[tex]D=6(r+16)\ldots\ldots\ldots\ldots\ldots(2)[/tex]Equating both the questions,
[tex]\begin{gathered} 8r=6(r+16) \\ 8r-6r=80 \\ 2r=80 \\ r=40\text{mph} \end{gathered}[/tex]Distance is,
[tex]\begin{gathered} D=8r \\ D=8\times\frac{80}{3} \\ D=213.3333\text{ miles} \end{gathered}[/tex]Answer:
Rate is 80/3 mph
distance is 213.3333 miles.