Answer:
The correct option is C
There are no possible solutions to the triangle
Explanation:
The sides of the triangle can be obtained using Cosine Rule as follows:
[tex]\begin{gathered} a^2=b^2+c^2-2bc\cos A \\ \\ So\text{ that} \\ A=\cos ^{-1}\frac{b^2+c^2-a^2}{2bc} \end{gathered}[/tex]
Using the given parameters, we have:
[tex]\begin{gathered} A=\cos ^{-1}\frac{5.14^2+3.78^2-1.72^2}{2(1.54\times3.78)} \\ \\ =\cos ^{-1}\frac{37.7496}{11.6424} \\ \\ =\cos ^{-1}3.24 \end{gathered}[/tex]
The last line is impossible
We conclude that there are no possible solutions for the triangle
