First, we compute the equation of the line that passes through (5,-5) and has slope -2/3 using the slope-point formula:
[tex]y-(-5)=-\frac{2}{3}(x-5)\text{.}[/tex]Solving for y we get:
[tex]\begin{gathered} y=-\frac{2}{3}x+\frac{10}{3}-5, \\ y=-\frac{2}{3}x-\frac{5}{3}\text{.} \end{gathered}[/tex]Therefore, (0,-5/3) is the y-intercept of the line.
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