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Leo had $91, which is 7 times as much money as Alison had. How muchmoney did Alison have?Select the correct solution method below, where x represents Alison's money.A. 7x = 91. Divide both sides by 7. Alison had $13.B. X- 7 = 91. Add 7 to both sides. Alison had $98.C. = 91. Multiply both sides by 7. Alison had $637.D. x+ 7 = 91. Subtract 7 from both sides. Alison had $846OLDNAT

Respuesta :

Given:

Leo had $91, which is 7 times as much money as Alison had.

Let x represents Alison's money.

So, the expression for Leo's money is,

[tex]7x=91[/tex]

Divide both sides of the above equation by 7.

[tex]\begin{gathered} \frac{7x}{7}=\frac{91}{7} \\ x=13 \end{gathered}[/tex]

So, Alison had $13.

Therefore, the correct solution method is

A) 7x = 91. Divide both sides by 7. Alison had $13.

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