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Consider the right triangle shown below that has an interior angle measure of θ radians.(a)The vertical leg of the triangle is how many times as long as the hypotenuse of the triangle?_____ times as long   (b)What is the value of sin(θ)? sin(θ)=   (c)The horizontal leg of the triangle is how many times as long as the hypotenuse of the triangle? _____times as long   (d)What is the value of cos(θ)? cos(θ)= (e)The vertical leg of the triangle is how many times as long as the horizontal leg of the triangle? ______times as long   (f)What is the value of tan(θ)? tan(θ)=

Consider the right triangle shown below that has an interior angle measure of θ radiansaThe vertical leg of the triangle is how many times as long as the hypote class=

Respuesta :

Part A

The vertical leg of the triangle = 1.01 cm

The hypotenuse = 2.1 cm

[tex]\frac{1.01}{2.1}=0.48[/tex]

• 0.48 times as long

Part B

[tex]\begin{gathered} \sin \theta=\frac{\text{Opposite}}{\text{Hypotenuse}} \\ \sin \theta=\frac{1.01}{2.1} \\ \sin \theta\approx0.48 \end{gathered}[/tex]

Part C

The horizontal leg of the triangle = 1.84 cm

The hypotenuse = 2.1 cm

[tex]\frac{1.84}{2.1}\approx0.88[/tex]

• 0.88 times as long

Part D

[tex]\begin{gathered} \cos \theta=\frac{\text{Adjacent}}{\text{Hypotenuse}} \\ \cos \theta=\frac{1.84}{2.1} \\ \cos \theta\approx0.88 \end{gathered}[/tex]

Part E

The vertical leg of the triangle = 1.01 cm

The horizontal leg of the triangle = 1.84 cm

[tex]\frac{1.01}{1.84}\approx0.55[/tex]

• 0.55 times as long

Part F

[tex]\begin{gathered} \tan \theta=\frac{\text{Opposite}}{\text{Adjacent}} \\ \tan \theta=\frac{1.01}{1.84} \\ \tan \theta\approx0.55 \end{gathered}[/tex]

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