What is the static force between two charged particles if the charge on object 1 is + 8.6 coulombs and the charge on object 2 is -7.4 coulombs. The distance between the objects is 5.5 meters

Given:
The charge on the object 1, q₁=8.6 C
The charge on object 2, q₂=-7.4 C
The distance between the objects, d=5.5 m
To find:
The force between the charges.
Explanation:
From Coulomb's law, the magnitude of the force between two charges is given by,
[tex]F=\frac{k|q_1||q_2|}{d^2}[/tex]On substituting the known values,
[tex]\begin{gathered} F=\frac{9\times10^9\times8.6\times7.4}{5.5^2} \\ =19\times10^9\text{ N} \\ =19\text{ GN} \end{gathered}[/tex]Final answer:
The force between the charges is 19 GN