Zoey purchased some beef and some chicken for a family barbeque. The beef cost $6.00 per pound and the chicken cost $4.50 per pound. She bought a total of 18 lb of meat and spent $96. How much of each type of meat did she purchase?

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Answer:

Zoey purchased some beef and chicken that combined cost $96 in total and was 18Ib in total weight, the cost of beef per pound is $6 and the cost of chicken per pound is $4.50, we have to find the amount of each that she bought:

The following mathematical equations can be constructed:

[tex]\begin{gathered} x+y=18\rightarrow(1)\Rightarrow\text{ Total weight} \\ \\ 6x+4.5y=96\rightarrow(2)\Rightarrow\text{ Total cost} \end{gathered}[/tex]

The (1) and (2) are the system of linear equations, x is the weight of beef, and y is the weight of chicken, the graphical solution for this system is as follows:

Therefore the solution is:

[tex]\begin{gathered} x=10Ib \\ \\ y=8Ib \end{gathered}[/tex]

The answers are, that she purchased (10) pounds of beef and (8) pounds of chicken

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