Given:
The amount of sample is
[tex]N_o=\text{ 10 g}[/tex]The half-life of the radioactive substance is
[tex]T_{\frac{1}{2}}=\text{ 6000 years}[/tex]Required: To find the amount of substance after t = 8000 years
Explanation:
The amount of substance after 8000 years can be calculated by the formula
[tex]N=N_o(\frac{1}{2})^{_\frac{t}{T_{\frac{1}{2}}}}[/tex]On substituting the values, the amount of substance will be
[tex]\begin{gathered} N=10(0.5)^{\frac{8000}{6000}} \\ =\text{ 3.97 g} \end{gathered}[/tex]Final Answer: The amount of substance present after 8000 years is 3.97 g
