I’m having trouble understanding how to solve number 1 under 5.3

Given
Solution
Formula
[tex]\begin{gathered} \text{Area =}\frac{1}{2}\times6\times4\times\sin 40^0 \\ \\ \text{Area =}\frac{1}{2}\times24\times\sin 40^0 \\ \\ \text{Area =}12\times\sin 40^0 \\ \\ \text{Area =}7.71345 \end{gathered}[/tex]The final answer
[tex]\text{Area =7.7}1345unit^2[/tex]