[tex]\begin{gathered} \text{Lateral Surface area of Trapezoid = perimeter of base x height} \\ \text{perimeter of base = 8 + 14 + 8 + 20 } \\ \text{ = 50 units} \\ \text{Height = 22 units } \\ \text{therefore,} \\ \text{Lateral surface area of Trapezoid = 50 units x 22 units} \\ \text{ = 1100 units}^{2^{}} \end{gathered}[/tex]
