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Consider the following consecutive integer problem.The sum of three consecutive odd integers is – 321. Find the three integers.Step 1 of 2: Set up an equation using the variable n as the smallest integer. Do not solve the problem.

Respuesta :

Let

n ----> the first odd integer

n+2 ----> the second consecutive odd integer

n+4---> the third consecutive odd integer

so

The equation that represents this problem is

n+(n+2)+(n+4)=-321

3n+6=-321

solve for n

3n=-321-6

3n=-327

n=-109

n+2=-109+2=-107

n+4=-109+4=--105

therefore

The numbers are

-109,-107 and -105

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