The given problem can be exemplified in the following diagram:
The area of a triangle is given by:
[tex]A=\frac{1}{2}bh[/tex]Where "b" is the base and "h" is the height. We have the following values:
[tex]\begin{gathered} b=4+4=8 \\ h=10 \end{gathered}[/tex]Replacing in the formula we get:
[tex]A=\frac{1}{2}(8)(10)[/tex]Solving the operation:
[tex]A=40[/tex]Therefore, the area is 40 square inches.
