Solve the following system of linear equations by choosing either substitution or elimination. You must show all work to receive credit.

To solve the system of equations given, we shall use the elimination method
[tex]\begin{gathered} -2x-5y=11---(1) \\ 3x+5y=-4---(2) \\ \text{Add equation (1) to equation (2)} \\ (-2x+3x)+(-5y+5y)=11+\lbrack-4\rbrack \\ x+0=7 \\ x=7 \\ \text{Substitute for the value of x into equation (1)} \\ -2x-5y=11 \\ -2(7)-5y=11 \\ -14-5y=11 \\ Add\text{ 14 to both sides of the equation} \\ -5y=25 \\ \text{Divide both sides by -5} \\ \frac{-5y}{-5}=\frac{25}{-5} \\ y=-5 \\ \text{The answer is} \\ x=7,y=-5 \end{gathered}[/tex]The answer is
x= 7 and y = -5