Given:
The height of the cone, h=4 in.
The diameter of the base of the cone, D=2 3/4 in.
The radius of the cone is,
[tex]\begin{gathered} r=\frac{D}{2} \\ =\frac{2\frac{3}{4}}{2} \\ =\frac{\frac{2\times4+3}{4}}{2} \\ =\frac{\frac{8+3}{4}}{2} \\ =\frac{\frac{11}{2}}{4} \\ =\frac{11}{2\times4} \\ =\frac{11}{8}in \end{gathered}[/tex]Now, the volume of the drinking cup in the shape of the cone is,
[tex]\begin{gathered} V=\frac{1}{3}\pi r^2h \\ =\frac{1}{3}\pi\times(\frac{11}{8})^{2^{}}\times4 \\ =7.9in^3 \end{gathered}[/tex]Therefore, the volume of the drinking cup in the shape of the cone is 7.9 cu in.
Hence, option B is correct.
