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The vapor pressure of the solution is 22.1 mmHg.
What is Raoult's law?
According to Raoult's law, the partial pressure of each component in a given solution is equal to the mole fraction of that component in the solution. This law applies to any given solution. The solution has a vapor pressure of 22 millibars of mercury.
The force that is exerted against the walls of a container by the vapors contained within that container is referred to as vapor pressure. It is a colligative property, which means that the rise or decrease in the amount of substance is dependent on the amount of solute that is now present.
The equation can be represented as:
Psolu = Psolv * Xsolv
Mole(KCl) = 40g/(74.5g/mol) = 0.537 mol; moles(H2O) = 250g/(18g/mol) = 13.9 mol water
But 0.537 mol KCl produces 1.074 mol of ions when dissolved in water.
Xsolv = 13.9 mol / (13.9 mol + 1.074 mol) = 0.9283;
Psolu = 23.76mmHg*0.9283 = 22.1 mmHg
Therefore, the vapor pressure of the solution is approximately 22 mmHg.
To know more about vapor pressure, refer to the following link:
https://brainly.com/question/12807275?
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