Answer:
2 C4H10,
13 O2,
8 CO2,
10 H2O.
Explanation:
Let's write the chemical equation:
[tex]C_4H_{10}+O_2\rightarrow CO_2+H_2O.[/tex]
The chemical equation is unbalanced for all the elements:
- On the left side we have 4 carbons but on the right side, we have 1.
- On the left side we have 2 oxygens but on the right side, we have 3.
- On the left side we have 10 hydrogens but on the right side, we have 2.
Let's put '4' moles beside CO2 to balance carbon:
[tex]C_4H_{10}+O_2\operatorname{\rightarrow}4CO_2+H_2O,[/tex]
We have hydrogen unbalanced, so putting '5' moles beside H2O, we obtain:
[tex]C_4H_{10}+O_2\operatorname{\rightarrow}4CO_2+5H_2O,[/tex]
On the left side, we have 2 oxygens but on the right side, we have 9 oxygens. Remember that the coefficients must be integers, so we cannot use fractions or decimals.
If we multiply by two each coefficient, we will obtain:
[tex]2C_4H_{10}+2O_2\operatorname{\rightarrow}8CO_2+10H_2O,[/tex]
But, oxygen is still unbalanced because on the right side we have 26 oxygens, but we can put '13' moles beside O2, and we will obtain the balanced chemical equation:
[tex]2C_4H_{10}+13O_2\operatorname{\rightarrow}8CO_2+10H_2O.[/tex]
