Given
The circle,
To find the center, radius and the equation of the circle.
Explanation:
It is given that,
From, the figure,
The center of the circle is (3,-1).
And, the radius of the circle is 4units.
Therefore, the equation of the circle is,
[tex]\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ (x-3)^2+(y-(-1))^2=4^2 \\ (x-3)^2+(y+1)^2=16 \\ x^2-6x+9+y^2+2y+1=16 \\ x^2+y^2-6x+2y+10-16=0 \\ x^2+y^2-6x+2y-6=0 \end{gathered}[/tex]
Hence, the center of the circle is (3,-1), the radius is 4units, and the equation of the circle is x²+y²-6x+2y-6=0.
