For the complete reaction of 130 ml 0.140 mole ,130 ml of 0.14 moles is required.
What is moles?
mole Is the unit of amount of substance in the international system of unit.
For the complete reaction of 130 ml 0.140 M CO (NO3)2, 130 ml of 0.14 is required.
The reaction of Li2S with CO(NO3)2 will be:
Li2S +CO(NO3)2-->2LiNO3+COS
Accordingly, 1 mole of Li2S completely reacts with 1 mole of CO(NO3)2.
moles of CO(NO3)2 - molarity Volume (L)
moles of = 0.140 M × 0.13 L
moles of CO(NO3)2 = 0.0182 moles.
The moles of Li2S reacts with CO(NO3)2 will be 0.0182 moles.
Volume of = Li2S= moles/molarity
Volume of = Li2S 0.0182/0.140
Volume of Li2S = 0.13 L
Volume of Li2S = 130 ml.
For the complete reaction of 130 ml 0.140 M , 130 ml of 0.14 is required.
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