Respuesta :

Given,

[tex]\begin{gathered} f(a)=a-2 \\ g(a)=-3a^2-1 \end{gathered}[/tex]

Then,

[tex](f\circ g)(a)=f(g(a))[/tex][tex]\begin{gathered} (f\circ g)(a)=f(-3a^2-1) \\ (f\circ g)(a)=(-3a^2-1)-2=-3a^2-3 \end{gathered}[/tex]

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