Given data:
The expression of the first option is,
[tex]\begin{gathered} \text{6(-4t+5})and\text{-2(15}-12t) \\ =-6(5-4t) \end{gathered}[/tex]
Thus, the above expression are not equivalent.
The expression in the second option is,
[tex]\begin{gathered} \frac{1}{5}(20t-15)\text{ and }4t-3 \\ 4t-3\text{ and 4t-3} \end{gathered}[/tex]
Thus, yes they are equivalent.
The expression in the third option is,
[tex]\begin{gathered} 1.5\text{ }-2\text{t and 0}.25(8-6t) \\ 1.5\text{ }-2\text{t and 2-1.5t} \end{gathered}[/tex]
Thus, the above expression are not equivalent.
The expression in fourth option is,
[tex]\begin{gathered} -3(t-7+5t+8)\text{ and }-18t-3 \\ -3(6t+1)\text{ and -18t-3} \\ -18t-3\text{ and -18t-3} \end{gathered}[/tex]
Thus, yes the above expression is equivalent.
