Given the system of equations:
[tex]\begin{cases}y=-\frac{2}{3}x+2 \\ y=\frac{1}{3}x+5\end{cases}[/tex]
we can graph both equations by finding the two intercepts in each case. For the first equation, we have:
[tex]\begin{gathered} y=-\frac{2}{3}x+2 \\ x=0\Rightarrow y=2 \\ (0,2) \\ y=0\Rightarrow-\frac{2}{3}x+2=0\Rightarrow-\frac{2}{3}x=-2\Rightarrow x=\frac{-2}{-\frac{2}{3}}=3 \\ (3,0) \end{gathered}[/tex]
for the second equation, we get:
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