Respuesta :

[tex]t=\frac{10\pi}{3}\equiv\frac{4}{3}\pi[/tex]

Therefore:

[tex]\begin{gathered} \cos (240)=\cos (\frac{4}{3}\pi)=-\frac{1}{2} \\ \sin (240)=\sin (\frac{4}{3}\pi)=-\frac{\sqrt[]{3}}{2} \\ (-\frac{1}{2},-\frac{\sqrt[]{3}}{2}) \end{gathered}[/tex]

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