Starting point:
A=(-4 , -8)
Final point:
B= (10 , 6)
First we have to substract the first x-value from the second, we will get:
10- (-4)=14
Now, substracting the first y-value form the second:
6 - (-8)= 6+8= 14
Since both legs are the same, this makes a triangle isoceles, this is because the slope of our line is 1
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{14}{14}=1[/tex]Now, we have to multiply the lenght of each leg by 3/10:
[tex]14*\frac{3}{10}=\frac{21}{5}=4.2[/tex]Remember that both length are the same. Therefore, we have to add 4.2 to -4 and -8 to find the coordinates of the point 3/10 of the way from A to B:
[tex]\begin{gathered} A=(-4.-8) \\ Ca=(-4+4.2,-8+4.2)=(0.2,-3.8) \end{gathered}[/tex]Answer: The coordinates are (0.2 , -3.8).
