part 2...expression using numbers and variables....need help with number 3 ..hello please help me with my math summer package and explain it in a way that a 7th grader can understand it

Explanation:
Given:
The number of figurine dolls in one case is
[tex]55dolls\text{ }in\text{ }1case[/tex]Part A:
To figure out the number of figurine dolls in
[tex]750cases,[/tex]We will use the formula
[tex]number(dolls)=number(dolls\text{ per case\rparen}\times number(cases)[/tex]By substituting the values, we will have
[tex]\begin{gathered} number(dolls)=number(dolls\text{percase}\operatorname{\rparen}\times(number(cases) \\ number(dolls)=55\times750 \\ number(dolls)=41250dolls \end{gathered}[/tex]Hence,
The final answer is
[tex]\begin{equation*} 41250dolls \end{equation*}[/tex]Part B:
To figure out the number of figurine dolls in
[tex]1000cases[/tex]By substituting the values, we will have
[tex]\begin{gathered} number(dolls)=number(dolls\text{percase}\operatorname{\rparen}\times number(cases) \\ number(dolls)=55\times1000 \\ number(dolls)=55000dolls \end{gathered}[/tex]Hence,
The final answer is
[tex]55000dolls[/tex]Part C:
To figure out the number of figurine dolls in
[tex]1250cases[/tex]By substituting the values, we will have
[tex]\begin{gathered} number(dolls)=number(dolls\text{percase}\operatorname{\rparen}\times number(cases) \\ number(dolls)=55\times1250 \\ number(dolls)=68750dolls \end{gathered}[/tex]Hence,
The final answer is
[tex]\begin{equation*} 68750dolls \end{equation*}[/tex]Part D:
Let the number of dolls be repressented by
[tex]d[/tex]To figure out the number of figurine dolls in
[tex]c\text{ }cases[/tex]By substituing the values, we will have
[tex]\begin{gathered} number(dolls)=number(dolls\text{percase}\operatorname{\rparen}\times number(cases) \\ d=55\times c \\ d=55c \end{gathered}[/tex]Hence,
The expression is given below as
[tex]d=55c[/tex]