Given:
[tex]\frac{y}{5}+\frac{y}{3}=8[/tex]
Required:
To correct the right option.
Explanation:
First of all we are going to calculate the given
[tex]\begin{gathered} \frac{y}{5}+\frac{y}{3}=8 \\ \\ \frac{3y+5y}{15}=\frac{8y}{15}=8 \\ \\ \end{gathered}[/tex]
or we can say
[tex]\begin{gathered} \frac{8y}{15}=0 \\ \\ 8y=0 \\ \\ y=0 \end{gathered}[/tex]
Required answer:
Option c is correct
[tex]y=0[/tex]
