The initial equation is:
[tex]x+3y=9[/tex]Now we write the equation in the slope intercept form so:
[tex]\begin{gathered} 3y=-x+9 \\ y=-\frac{1}{3}x+3 \end{gathered}[/tex]Now we know that the intercept with the y axis is 3, and we can calculate the intercept in the x axis by replacing y = 0 so:
[tex]\begin{gathered} 0=-\frac{1}{3}x+3 \\ \frac{1}{3}x=3 \\ x=3\cdot3 \\ x=9 \end{gathered}[/tex]Now we can graph the equation with the coordinates ( 0, 3 ) and ( 9, 0 ) so:
