The recursive formula is given by
[tex]f(n)=f(n-1)-2[/tex]Now let
[tex]f(n-1)=3[/tex]Then
[tex]f(n)=f(n-1)-2\Rightarrow f(n)=3-2\Rightarrow f(n)=1[/tex]And let
[tex]f(n-1)=-1[/tex]Then
[tex]f(n)=f(n-1)-2\Rightarrow f(n)=-1-2\Rightarrow-3[/tex]So the answer is 3,1,-1,-3