Let, larger number be x and smaller number be y.
Condition 1: The summ of two numbers is 134.
It can be written as,
[tex]x+y=134\ldots\ldots\text{.}(1)[/tex]Condition 2: If three times the smaller number is subtracted from the larger number, the result is 18.
The equation is,
[tex]x-3y=18\ldots\ldots\ldots\text{.}\mathrm{}(2)[/tex]Solving equation 1 and 2,
[tex]\begin{gathered} \text{subtract equation (2) from (1),} \\ x+y-(x-3y)=134-18 \\ x+y-x+3y=116 \\ 4y=116 \\ y=29 \end{gathered}[/tex]Out the value of y=29 in equation (1),
[tex]\begin{gathered} x+y=134 \\ x+29=134 \\ x=105 \end{gathered}[/tex]Answer:
Larger number is x=105
Smaller number is y=29.
