Answer:
After 30.2 minutes, the two pools will have the same amount of water.
Explanation:
(a)The general structure of the equation is that of a linear function:
[tex]y=mx+b[/tex]
(b)
Variable Definition
Let the amount of water in the pool after m minutes = y
Let the number of minutes the pool has been drained = m
Left-Side Expression:
Mr Zoetrope's pool has 10,858 gallons and is draining 150 gallons per minute.
[tex]\implies y=10,858-150m[/tex]
Right-Side Expression:
Mrs Homer's pool has 9,650 gallons and is draining 110 gallons per minute.
[tex]\implies y=9650-110m[/tex]
The equation
[tex]10858-150m=9650-110m[/tex]
We solve for m.
[tex]\begin{gathered} 10,858-9650=150m-110m \\ 1208=40m \\ m=30.2 \end{gathered}[/tex]
After 30.2 minutes, the two pools will have the same amount of water.
