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In a class of students, the following data table summarizes how many students have acat or a dog. What is the probability that a student has a dog given that they do nothave a cat?Has a cat Does not have a cat39Has a dogDoes not have a dog213Answer:Submit Answer

In a class of students the following data table summarizes how many students have acat or a dog What is the probability that a student has a dog given that they class=

Respuesta :

[tex]\frac{1}{3}[/tex]

Explanation

Probability is simply how likely something is to happen. Probability of event to happen P(E) = Number of favourable outcomes/Total Number of outcomes.

[tex]P=\frac{favorable\text{ outcomes}}{\text{total outcomes}}[/tex]

so

Step 1

Let

Number of studenst tha have a dog, given the do ot have a cat

=9

so

[tex]\text{Favorable ourcomes=9}[/tex]

and

total students = 3+9+2+13=27

so

[tex]\text{total outcomes = 27}[/tex]

finally, replace

[tex]\begin{gathered} P=\frac{favorable\text{ outcomes}}{\text{total outcomes}} \\ P=\frac{9}{27} \\ P=\frac{1}{3} \end{gathered}[/tex]

therefore, the answer is

[tex]\frac{1}{3}[/tex]

I hope this helps you

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