What is the distance between a points (3,4) and (-2,-2) (round to the nearest 10th, if necessary) distance between the points (three, four) and (-2, -2) is blank units?

Answer:
The coordinates given in the question are
[tex]\begin{gathered} (x_1,y_1)\Rightarrow(3,4) \\ (x_2,y_2\Rightarrow(-2,-2) \end{gathered}[/tex]Concept:
The distance between two points of a line is given below as
[tex]d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]By substituting the values, we will have
[tex]\begin{gathered} d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ d=\sqrt[]{(-2-3)^2+(-2-4)^2} \\ d=\sqrt[]{(-5)^2+(-6)^2} \\ d=\sqrt[]{25+36} \\ d=\sqrt[]{61} \\ d=7.8\text{ units} \end{gathered}[/tex]Hence,
The final answer is
[tex]\Rightarrow7.8[/tex]