Module 2 Open-Ended Problem:3x+9f(x)=2x2Find f(5). Write your answer as a fraction in lowest terms.

Answer:
[tex]f(5)\text{ = }\frac{12}{25}[/tex]Explanation:
Here, we want to get the value of the farction in the lowest form
To do this,we need to susbtitute the value 5 for x
We have this as follows:
[tex]f(5)\text{ = }\frac{3(5)\text{ + 9}}{2(5)^2}\text{ = }\frac{24}{50}\text{ = }\frac{12}{25}[/tex]