We define the two numbers as x and y.
From the statement, we know that:
• (1), the difference between the two numbers is 28:
[tex]x-y=28,[/tex]• (2), the first number (x) is three times the other number (y):
[tex]x=3y\text{.}[/tex]Replacing the equation from point (2) in point (1), we have the following equation for number y:
[tex]\begin{gathered} 3y-y=28, \\ 2y=28. \end{gathered}[/tex]Solving for y, we get:
[tex]y=\frac{28}{2}=14.[/tex]Replacing this result in the equation from point (2), we get:
[tex]x=3\cdot14=42.[/tex]So the numbers are x = 42 and y = 14.
Answer
A. 14 and 42
